are 2,4,1. ∴‌‌ The d.r.s. of any line parallel to it are also 2,4,1. The equation of the line passing through A(1,3,2) is ‌
x−1
2
=‌
y−3
4
=‌
z−2
1
=λ (say) Then, any point on the line is B≡(2λ+1,4λ+3,λ+2) The point B lies on the plane 3x+y+2z=5. ‌∴‌‌3(2λ+1)+4λ+3+2(λ+2)=5 ‌⇒12λ+10=5 ‌∴B≡(‌