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MHTCET 11 May 2024 Shift 2 Paper

Question : 93 of 150

Marks: +1, -0

\mathrm{H}_{2} \mathrm{SO}_{4}

Solution:

Concept:

Sulfuric acid is a strong diprotic acid, so each molecule produces two hydrogen ions.

Explanation:

A centimolar solution means concentration

= 0.01 \ \mathrm{M} = 10^{-2} \ \mathrm{M}

Since

\mathrm{H}_2\mathrm{SO}_4

gives 2 moles of

\mathrm{H}^+

per mole of acid:

[\mathrm{H}^+] = 2 \times 10^{-2} \ \mathrm{M}

Now calculate pH:

\mathrm{pH} = -\log_{10}[\mathrm{H}^+] = -\log_{10}(2 \times 10^{-2})

= -\log_{10}2 - \log_{10}10^{-2}

= -\log_{10}2 + 2

= 2 - 0.3010 = 1.7

Answer:

1.7

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