MHTCET 11 May 2024 Shift 1 Paper

Concept:The oxidation number of sulfur is found using the known oxidation number of oxygen and the total charge of the ion.Explanation:In $\mathrm{SO}_{3}^{2-}$, oxygen has an oxidation number of $-2$.Let the oxidation number of sulfur be $x$.The ion has one sulfur atom and three oxygen atoms, and its total charge is $-2$.So, the equation is:$$x + 3(-2) = -2$$Simplify:$$x - 6 = -2$$Solve for $x$:$$x = -2 + 6$$$$x = +4$$Thus, the oxidation number of sulfur in $\mathrm{SO}_{3}^{2-}$ is $+4$.Answer:$+4$ (Option C)