MHTCET 11 Apr 2026 Shift 2 Paper

Concept:Oxidative cleavage of the alkene double bond using acidic $\mathrm{KMnO}_{4}$ converts each double-bond carbon into a carboxylic acid group, opening a cycloalkene ring.Explanation:Cyclohexene has one double bond in a six-membered ring.Acidified $\mathrm{KMnO}_{4}$ is a strong oxidising agent that breaks the $\mathrm{C=C}$ bond completely.Because the double bond is inside the ring, breaking it opens the ring.Each carbon of the double bond becomes a $\mathrm{-COOH}$ group.The product has a straight chain of six carbons with carboxylic acid groups at both ends:$$\mathrm{HOOC-\left(CH_2\right)_4-COOH}$$This compound is hexane-1,6-dioic acid, commonly called adipic acid.Answer:Cyclohexene on oxidation by $\mathrm{KMnO}_{4}$ in dilute $\mathrm{H}_{2}\mathrm{SO}_{4}$ produces hexane-1,6-dioic acid.Correct option: C.