MHTCET 11 Apr 2026 Shift 1 Paper

Concept:The magnifying power of a telescope is the ratio of the focal length of the objective to that of the eyepiece.Explanation:For a telescope in normal adjustment, the magnifying power is given by:$$M = \frac{f_o}{f_e}$$Here, $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.For a large magnifying power, $M$ should be large.From the formula, $M$ becomes large when the numerator $f_o$ is large and the denominator $f_e$ is small.Thus, the objective lens must have a large focal length, while the eyepiece must have a small focal length.This matches the condition given in the options.Answer:Option B — focal length of objective is large.