MHTCET 10 May 2024 Shift 1 Paper

Concept:The oxidation state of an element is calculated by setting the total charge of a neutral molecule to zero.Explanation:In $\mathrm{I}_{2}\mathrm{Cl}_{6}$, chlorine is more electronegative than iodine.So each chlorine atom has an oxidation state of $-1$.There are six chlorine atoms, giving a total of $6 \times (-1) = -6$.Let the oxidation state of each iodine atom be $x$.Since the molecule is neutral, the sum of oxidation states is zero:$$2x + 6(-1) = 0$$Simplify:$$2x - 6 = 0$$$$2x = 6$$$$x = +3$$Thus, iodine has an oxidation state of $+3$ in $\mathrm{I}_{2}\mathrm{Cl}_{6}$.Answer:$+3$ (Option C).