MHTCET 10 May 2024 Shift 1 Paper

Concept:The sum of all oxidation numbers in a neutral compound is zero.Explanation:In $\mathrm{K}_{2}\mathrm{C}_{2}\mathrm{O}_{4}$, potassium is in Group 1, so its oxidation number is $+1$.Oxygen usually has an oxidation number of $-2$.Let the oxidation number of carbon be $x$.There are 2 potassium atoms, 2 carbon atoms, and 4 oxygen atoms.Write the neutrality equation:$$2(+1) + 2x + 4(-2) = 0$$Simplify:$$2 + 2x - 8 = 0$$$$2x - 6 = 0$$$$2x = 6$$$$x = +3$$Thus, the oxidation number of each carbon atom is $+3$.Answer:Option C: $+3$