(c) According to Kepler's third law, time period T2=‌
4Ï€2
GM
a3 where, a is the semi-major axis, ⇒a‌‌=[‌
76×86400×365×6.67×2×1030
4×3.14×3.14
]1∕3 ‌‌=2.7×1012m Also in case of ellipse, 2a‌‌=‌ perihelion ‌+‌ aphelion ‌ ⇒‌‌‌ Aphelion ‌‌‌=2a−‌ perihelion ‌ ‌‌=2×2.7×1012−8.9×1010 ‌‌≈5.3×1012m