If A = {bmatrix} -5 & 2 \\ 1 & -3 {bmatrix}, then adj A is

Correct Answer is : [−3−2−1−5]{bmatrix} -3-2 \\ -1-5 {bmatrix}[−3−2−1−5]

{bmatrix} -3-2 \\ -1-5 {bmatrix}

{bmatrix} 5 & 1 \\ 2 & 3 {bmatrix}

{bmatrix} 3 & -2 \\ -1 & 5 {bmatrix}

{bmatrix} 3 & 2 \\ 1 & 5 {bmatrix}

Correct Answer is : [−3−2−1−5]{bmatrix} -3-2 \\ -1-5 {bmatrix}[−3−2−1−5]

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Matrices

Question : 19 of 36

Marks: +1, -0

A = \begin{bmatrix} -5 & 2 \\ 1 & -3 \end{bmatrix},

A

Solution:

Concept:

For a

2 \times 2

matrix

\begin{bmatrix} a & b \\ c & d \end{bmatrix}

, the adjoint is

\begin{bmatrix} d & -b \\ -c & a \end{bmatrix}

Explanation:

Given

A = \begin{bmatrix} -5 & 2 \\ 1 & -3 \end{bmatrix}

, identify

a = -5

b = 2

c = 1

d = -3

Then adj

A = \begin{bmatrix} d & -b \\ -c & a \end{bmatrix} = \begin{bmatrix} -3 & -2 \\ -1 & -5 \end{bmatrix}

This matches option A (interpreting the given formatting as a

2 \times 2

matrix with entries

-3

-2

in the first row;

-1

-5

in the second row).

Answer:

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