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MAT Exam 2025 Paper

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Question : 90 of 150

Marks: +1, -0

At the end of the year, profit of ₹

3,15,000

is earned by a partnership firm having Neha, Anmol, Piya and Rahul as partners. In the business, the share of Anmol is 3/4 of that of Neha's share and Piya share is 2/3 of Anmol's share and Rahul's share is 3/4th of Piya's share. What is the difference between the share's profit of Neha and Rahul against that of Anmol and Piya?

₹ 19,700
₹ 17,280
₹ 15,000
₹ 14,830
SECTION-D : Data Analysis & Sufficiency

Solution:

Concept:

Convert each partner's share into a fraction of Neha's share, then compare the required sum of shares.

Explanation:

Let Neha's share be

x

.

Anmol's share

= \frac{3}{4}x

.

Piya's share

= \frac{2}{3} \times \frac{3}{4}x = \frac{1}{2}x

.

Rahul's share

= \frac{3}{4} \times \frac{1}{2}x = \frac{3}{8}x

.

Total profit:

x + \frac{3}{4}x + \frac{1}{2}x + \frac{3}{8}x = 315000

\frac{21}{8}x = 315000

x = \frac{315000 \times 8}{21} = 120000

So, Neha

= 120000

, Anmol

= 90000

, Piya

= 60000

, Rahul

= 45000

.

Now compare:

Neha

+

Rahul

= 120000 + 45000 = 165000

Anmol

+

Piya

= 90000 + 60000 = 150000

Difference

= 165000 - 150000 = 15000

Answer:

₹ 15,000, i.e. option C.

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