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MAT Exam 2025 Paper

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Question : 62 of 150

Marks: +1, -0

An aeroplane starts from New Delhi to reach its destination, Kanyakumari, 2,280 km in 3 hours 20 minutes. But due to turbulent weather, its speed had to be reduced. Thus, it reached its destination 40 minutes late. By how much was its speed reduced?

132 kmph
125 kmph
121 kmph
114 kmph

Solution:

Concept:

Speed reduction is the difference between the original speed and the reduced speed.

Explanation:

Original time

= 3

hours

20

minutes

= 3 + \frac{20}{60} = \frac{10}{3}

hours.

Original speed

= \frac{2280}{10/3} = 2280 \times \frac{3}{10} = 684

km/hr.

Due to delay, new time

= \frac{10}{3} + \frac{40}{60} = \frac{10}{3} + \frac{2}{3} = 4

hours.

Reduced speed

= \frac{2280}{4} = 570

km/hr.

Speed reduction

= 684 - 570 = 114

km/hr.

Answer:

114

km/hr, i.e., Option D.

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