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MAT Exam 2024 Paper

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Question : 66 of 150

Marks: +1, -0

A man left one-third of his property for his wife, one-half for his son and the remainder for his daughter. If the daughter's share was worth ₹ 44000, how much money did the man leave?

₹ 245,000
₹ 260,000
₹264000
₹ 275,000

Solution:

Concept:

The daughter receives the remaining part after wife and son get their shares.

Explanation:

Let the total property be ₹

x

.

Wife’s share

= \frac{1}{3}x

Son’s share

= \frac{1}{2}x

Remainder for daughter:

x - \left(\frac{1}{3}x + \frac{1}{2}x\right) = 44000

x - \frac{1}{3}x - \frac{1}{2}x = 44000

\frac{6x - 2x - 3x}{6} = 44000

\frac{x}{6} = 44000

x = 44000 \times 6 = ₹ 2,64,000

Answer:

₹ 2,64,000, i.e., Option C.

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