MAT Exam 2023 Paper

Concept:This is a year-based ordering puzzle; check whether the clues give one unique arrangement before deciding who was born in $2010$.Explanation:The possible pairs with an $11$-year gap are $(1994, 2005)$ and $(1999, 2010)$.Isha–Faruk and Bala–Hardev must use these pairs, but no clue fixes which pair is used by which relation.If Isha $=1994$, Faruk $=2005$, Bala $=1999$ and Hardev $=2010$, then Devraj $=1967$, Gagan $=1976$, Ekta $=1982$ and Chintu $=2013$.In this arrangement Hardev, who is immediately before Chintu, was born in $2010$.But another valid arrangement is: Isha $=1999$, Faruk $=2010$, Bala $=1994$, Hardev $=2005$, Gagan $=1982$, Ekta $=2013$, with Devraj and Chintu taking $1967$ and $1976$ in either order.All the given age and position conditions remain true here, and in this case Faruk was born in $2010$.Thus two different arrangements satisfy the data and give different persons for $2010$.Answer:The given information is insufficient to determine one unique person; no single option can be concluded. Option A is possible in one valid arrangement and Option D is possible in another.