Concept:The two tracks touch only at point
A.
So Ram and Rahim can meet again only when both reach
A at the same time after completing whole numbers of rounds.
Explanation:Radius of track
T1 is
100m and radius of track
T2 is
20m.
Circumference of
T1=2π(100)=200πm.
Circumference of
T2=2π(20)=40πm.
Therefore, ratio of circumferences
=200π:40π=5:1.
Speeds are
15km/hr and
5km/hr, so speed ratio
=15:5=3:1.
Time for one round
=speedcircumference.
Hence, time per round ratio:
35:11=5:3.
So Ram takes
5 units of time per round while Rahim takes
3 units.
Let Ram make
n rounds and Rahim make
m rounds before meeting again.
Meeting condition:
5n=3m.
Smallest whole-number solution is
n=3,
m=5.
Thus Ram completes
3 full rounds, and Rahim completes
5 full rounds at their first meeting after start.
Answer:Ram makes
3 full rounds before meeting Rahim again for the first time.
Correct option: B.