MAT Exam 2020 Paper

Concept:The bridge is destroyed if at least one bomber hits it.Equivalent probability is $1 - P(\text{no bomber hits})$.Explanation:Compute the probability that each bomber misses:First bomber misses: $1 - 0.3 = 0.7$Second bomber misses: $1 - 0.4 = 0.6$Third bomber misses: $1 - 0.7 = 0.3$Since the bombers act independently, the probability that all three miss is:$0.7 \times 0.6 \times 0.3 = 0.126$Therefore, the probability of the bridge being destroyed is:$1 - 0.126 = 0.874$Answer:The correct option is A. $0.874$