Radius of inner track =100m Radius of outer track =102m ∴ Distance covered by A=2×π×100=200πm Distance covered by B=2×π×102=204πm Time taken by A=1‌min‌30‌s=90s Time taken by B=1‌min‌32‌s=92s ∴‌‌SA=‌
200Ï€
90
,SB=‌
204Ï€
92
SA:SB=‌
200Ï€
90
:‌
204Ï€
92
=18400:18360 So, SA>SB i.e., speed of A is greater than B.