(a) For first cube, probability of getting red face =
and probability of getting blue late =
Now, let the number of faces which are coloured red in colour = x
∴ Number of blue faces = 6 - x
Similarly, for second cube,
Probability of getting red face =
and probability of getting blue face =
Then, by given condition,
× +
×= x+= = 4x + 6 = 18
4x = 18 - 6 = 12
x =
= 3
∴ Number of red faces on second cube = 3