Management Aptitude Test Feb 2012 Paper

(2) External surface area of the shuttlecock = External surface area of frustrum + External surface area of hemisphere

= π(R + r )l = 2π r
= π (R + r) (√h2+(R+r)2) + 2π r
where R = 2.5 cm, r = 1 cm, h = 6 cm
∴ Required surface area
=

22

7

x 3.5 √36+1.52 + 2 x

22

7

x 1

= 22 x 0.5√38.25 + 6.28
= 11 x 6.18 + 6.28 = 74.26 cm2