Management Aptitude Test 2016 Paper

(a) ∵ Speed of first train,
s1 = 48 km/h =

40

3

m/s
and speed of second train,
s2 = 42 km/h =

35

3

m/s
Let the length of first train be d m.
Then, length of second train =

d

2

m
∴ Relative speed = s1 + s2
=

40

3

+

35

3

=

75

3

= 25 m/s
According to the question,
d +

d

2

= 25 x 12
⇒

3d

2

= 25 x 12
⇒ d =

25×12×2

3

= 200 m
Again, let length of the platform be l m.
Then, 200 + l =

40

3

x 45
⇒ 200 + l = 600
⇒ l = 600 - 200 = 400 m