Management Aptitude Test 2015 Paper

(d ) Given, pipes A and B can fill a tank = 10 h,
B and C can fill it in 12 h,
A and C can fill it in 8 h.
Now, tank filled by all the pipes together
2(A + B + C ) =

1

10

+

1

12

+

1

8

∵ LCM of 10, 12, 8 = 120.
=

1

2

(

1

10

+

1

12

+

1

8

)
=

1

2

(

12+10+15

120

)
=

1

2

×

37

120

∴ Pipe 8 alone can fill the tank in
=

1

2

×

37

120

−

1

8

=

370−300

2400

=

70

2400

=

7

240

Hence, B alone can fill the tank in

240

7

h