Given: Diameter of circle = 26cm Radius OA = 13cm Length of chord AB = 10cm Concepts used: perpendicular drawn from the centre of the circle to the chord, bisects the chord Calculation: AC=AB/2=10/2=5cm ….(⊥ drawn from the centre of the circle, bisects the chord) using Pythagorean Theorem OA2=OC2+AC2 ⇒132=OC2+52 ⇒169=OC2+25 ⇒OC2=144 OC = 12cm ∴ The perpendicular distance of the chord from centre is 12 cm