The equivalent form of the equation log (x-2)+(x+3)=0 is

Correct Answer is : None of these

Correct Answer is : None of these

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Logarithms

Question : 74 of 85

Marks: +1, -0

(x-2)+\log(x+3)=0

Solution:

Concept:

Combine logarithms using the product rule, then convert to exponential form.

Explanation:

Given:

\log(x-2) + \log(x+3) = 0

Using the product rule:

\log[(x-2)(x+3)] = 0

Assuming base 10 (common logarithm):

(x-2)(x+3) = 10^0 = 1

Expand:

x^2 + x - 6 = 1

Thus:

x^2 + x - 7 = 0

None of the given options match this equation.

Answer:

The equivalent form is

x^2 + x - 7 = 0

, which is not listed among A, B, or C.

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