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LIC AAO Model Paper 6

Question : 37 of 160

Marks: +1, -0

Solution:

1 man will complete the work in = 6 x 12 = 72 days

1 woman will complete the work in = 8 x 18 = 144 days

1 child will complete the work in = 18 x 10= 180 days

4 men + 12 women + 20 children’s 2 days' work

= 2

\left(\frac{4}{72}+\frac{12}{144}+\frac{20}{180}\right)

= 2

\left(\frac{1}{18}+\frac{1}{12}+\frac{1}{9}\right)

\frac{2(2+3+4)}{36}

\frac{1}{2}

∴ Remaining work =

\frac{1}{2}

∴ Required number of men = 72 ×

\frac{1}{2}

= 36

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