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KVPY SA Exam 2013 Question Paper
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© examsnet.com
Question : 2
Total: 80
If a,b are natural numbers such that
2013
+
a
2
=
b
2
, then the minimum possible value of ab is
671
668
658
645
Validate
Solution:
(b ñ a) (b + a) = 2013 = 3 × 11 × 61
ab minimum when b - a = 33
b + a = 61
a = 14
ab = 14 × 47 = 658
© examsnet.com
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