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KVPY SA Exam 2012 Question Paper
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© examsnet.com
Question : 64
Total: 80
A train leaves Pune at 7:30 am and reaches Mumbai at 11:30 am. Another train leaves Mumbai at 9:30 am and reaches Pune at 1:00 pm. Assuming that the two trains travel at constant speeds, at what time do the two trains cross each other?
10:20 am
11:30 am
10:26 am
data not sufficient
Validate
Solution:
First train from Pune to Mumbai takes 4hrs.
Second train from Mumbai to Pune takes 3.5hrs.
Speed of train from Pune to Mumbai is
V
1
=
d
4
Speed of train from Mumbai to Pune is
V
2
=
d
3.5
Distance traveled by first train till 9:30 is
x
=
d
4
×
2
=
d
2
Say now both trains meet after time from 9:30
x
d
∕
4
=
d
2
−
x
d
3.5
⇒
4
x
d
=
3.5
2
−
3.5
x
d
⇒
7.5
x
d
=
3.5
2
⇒
15
x
=
3.5
d
⇒
30
x
=
7
d
time taken by first train from 9: 30 is
4
x
d
=
4
(
7
30
)
=
14
15
= 56 min
Then both train meet at 9.30 + 56 min = 10 : 26 am
© examsnet.com
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