Kerala KEAM 6 June 2024 Solved Paper

Concept:Identify the type of isomerism for each coordination compound based on its structure and ligand properties.Explanation:(a) $\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]$ is square planar, showing cis/trans isomerism → geometrical isomerism (iv).(b) $\left[\mathrm{Co}(e n)_3\right]^{3+}$ has three bidentate ligands; it forms a chiral propeller structure → optical isomerism (iii).(c) $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Br}$ can exchange $\mathrm{SO}_4^{2-}$ and $\mathrm{Br}^-$ between coordination sphere and counterion → ionisation isomerism (i).(d) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_2\right)\right] \mathrm{Cl}_2$ has $\mathrm{NO}_2^-$ which can bind through N or O → linkage isomerism (ii).The correct matches are (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii). Among the options, only Option C has (a)-(iv), (b)-(iii), and (d)-(ii) correct, while (c) is incorrectly linked; however, it is the best available choice.