To determine the number of sigma bonds, we need to count the sigma bonds in each bond in the given structure:
The given compound is:
CH3CH=C=CH−C≡C−H1. Sigma bonds in single bonds:
- Each C-H bond is a single bond, and there are 4 C-H bonds (1 from each methyl group and 1 from the terminal CH group) contributing 4 sigma bonds.
- Each C-C bond in the structure is a single bond (sigma bond), and there are 3 C-C bonds, contributing 3 sigma bonds.
2. Sigma bonds in double bonds:
- Each double bond consists of 1 sigma bond and 1 pi bond. There are 2 double bonds in the compound (C=C), contributing 2 sigma bonds.
3. Sigma bonds in triple bonds:
- Each triple bond consists of 1 sigma bond and 2 pi bonds. There is 1 triple bond (C≡C) contributing 1 sigma bond.
Now, adding all the sigma bonds together:
- 4 sigma bonds from C-H bonds,
- 3 sigma bonds from C-C single bonds,
- 2 sigma bonds from C=C double bonds,
- 1 sigma bond from C≡C triple bond.
Thus, the total number of sigma bonds is:
4+3+2+1=11Thus, the correct answer is option (B), 11. Quick Tip: To count sigma bonds, remember that every single bond, one bond in a double bond, and one bond in a triple bond is a sigma bond. Double bonds contribute 1 sigma bond, and triple bonds contribute 1 sigma bond.