Kerala KEAM 5 June 2024 Solved Paper

The quantity of heat conducted through a rod is governed by the formula for thermal conduction:$$Q = \frac{Q_1}{\Delta T_1} = \frac{Q_2}{\Delta T_2}$$where:- $Q_1$ is the heat conducted in 1 second with the temperature difference $\Delta T_1 = 120^\circ C - 100^\circ C = 20^\circ C$,- $Q_2$ is the heat conducted in 1 second with the temperature difference $\Delta T_2 = 220^\circ C - 200^\circ C = 20^\circ C$.Given that $Q_1 = 5 \, J/s$, the heat conducted in 1 second is 5 J for a temperature difference of 20°C.When the temperature difference is also 20°C (from 200°C to 220°C), the heat conducted per second will remain the same, which is 5 J.Now, the total heat conducted in 10 seconds is:$$Q_{total} = 5 \times 10 = 50 \, J$$Thus, the quantity of heat conducted in 10 seconds is:$$\boxed{50 \, J}$$ Quick Tip: The quantity of heat conducted is directly proportional to the temperature difference when all other conditions remain constant. So, if the temperature difference remains the same, the heat conducted remains constant.