Let equation of parabola be (y−k)2=4a(x−h) Given, vertex (h,k)=(−6,2) ∴‌‌(y−2)2=4a(x+6) This equation is passing through (−3,5), ∴‌‌(5−2)2=4a(−3+6) ⇒9=4a(3) ⇒a=3∕4 ∴ Required equation of parabola (y−2)2=4(3/4)(x+6) ⇒‌‌(y−2)2=3x+18