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KEAM 2019 Math Paper
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© examsnet.com
Question : 117
Total: 121
lim
n
→
∞
{
‌
1
1
−
n
2
+
‌
2
1
−
n
2
+
.
.
.
.
+
‌
n
1
−
n
2
}
is equal to
0
‌
−
1
2
‌
1
2
1
3
Validate
Solution:
lim
n
→
∞
{
‌
1
1
−
n
2
+
‌
2
1
−
n
2
+
.
.
.
+
‌
n
1
−
n
2
}
‌
‌
=
lim
n
→
∞
‌
1
+
2
+
3
+
.
.
.
.
+
n
1
−
n
2
‌
‌
=
lim
n
→
∞
‌
Σ
n
1
−
n
2
=
lim
n
→
∞
‌
n
(
n
+
1
)
2
(
1
−
n
2
)
‌
‌
=
lim
n
→
∞
‌
1
+
1
n
2
[
‌
1
n
2
−
1
]
=
−
‌
1
2
© examsnet.com
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