f(x)=px2+qx+r f(−4)=0 ⇒‌‌16p−4q+r=0.....(i) One root is ‌‌x=−4 and ‌‌f(5)=−3f(2) 25p+5q+r=−3(4p+2q+r) ⇒‌‌37p+11q+4r=0.....(ii) Eq. (ii) - Eq. (i), we get ⇒‌‌−27p+27q=0 ⇒‌‌,‌‌p=q Then, equation is px2+qx+r=0 Roots =−4,α Sum of roots =−4x+α=−‌