Let ‌‌x=a−r,y=a,z=a+r Now, we have x+y+z=−3 ∴‌‌a−r+a+a+r=−3 ⇒‌‌3a=−3 ⇒‌‌a=−1 Again, ‌‌xyz=8 ∴‌‌(a−r)(a)(a+r)=8 ⇒‌‌a(a2−r2)=8 ⇒‌‌−1(1−r2)=8 ⇒‌‌−1+r2=8 ⇒‌‌r2=9 ⇒‌‌‌‌r=±3 ∴‌‌x,y,z are -4,-1,2 or 2,-1,-4