Total number of monohalogenated products of 2, 4,4 -trimethylhexane are six.
1
H3C
−
2
CH2
|
CH3
−
3
CH2
−
CH3
|
4
C
|
CH3
−
5
CH2
−
6
CH3
(i) 2 monohalogenated products by replacing two −CH3 groups at C2 and C4 position. (ii) 4 monohalogenated products by replacing H by Cl at C2,C3,C5,C6 positions. Thus, total 6 isomers are possible.