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KEAM 2016 Physics and Chemistry Paper

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Question : 77

Total: 120

The correct descending order of the heat liberated (in kJ ) during the neutralisation of the acids (CH3COOH(W),HF(X),HCOOH(Y) and HCN(Z) under identical conditions (Ka of CH3COOH=1.8×10−5,HCOOH=1.8×10−4 , HCN=4.9×10−10 and HF=3.2×10−4) is

Y>X>Z>W
X>Y>W>Z
W>X>Y>Z
Z>W>Y>X
Z>Y>X>W

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