Given equation is x2−6x+c=0 Roots of the equation are α and α2. ∴‌‌α+α2=6 and α⋅α2=c ⇒‌‌α3=c From Eq. (i), we have α+α2−6=0 ⇒‌‌α2+α−6=0 ⇒‌‌(α+3)(α−2)=0 ⇒‌‌α=−3,2 ∵ Value of c is positive. ∴‌‌α=2 and c=(2)3=8