y2−4x−2y−3=0 ⇒(y2−2y)=4x+3 ⇒(y−1)2−1=4x+3 ⇒(y−1)2=4(x+1) Shift the origin to (-1,1) ⇒Y2=4X ⇒ Focus is at (1,0) Hence, focus of original parabola becomes (1−1,0+1)=(0,1) ∴ Equation of latusrectum is x=0. ∴ Point of intersection of parabola and latusrectum is y2−2y−3=0⇒y=−1 or 3 So, required points are (0,−1),(0,3)