Given equation is x∣x∣−5x−6=0.....(i) Case I When x>0; then equation is x2−5x−6=0⇒(x−6)(x+1)=0∴x=−1 or 6 But x>0⇒x=−1∴x=6Case II When x<0, then equation is −x2−5x−6=0⇒x2+5x+6=0⇒(x+2)(x+3)=0⇒x=−2 or -3 So, the required roots are −3,−2,1,6.∴ Product of the roots =(−3)(−2)(1)(6)=36