∵ Freezing point of the aqueous solution =−0.186∘C ∴ Depression in freezing point, ∆Tf=0∘C−(−0.186∘C) =+0.186∘C=+0.186~K We know that, ∆Tf=Kf⋅m.....(i) and elevation in boiling point, ∆Tb=Kb⋅m.....(ii) Eq. (i) Eq. (ii) gives ‌