Concept:Use differentiation to convert the given integral equation into a simple first-order differential equation, then solve it by separating variables.
Explanation:Start with the given equation:
∫xf(x)dx+2f(x)=0Differentiate both sides with respect to
x.
The derivative of
∫xf(x)dx is
xf(x), and the derivative of
2f(x) is
21f′(x).
So we get:
xf(x)+2f′(x)=0Multiply through by
2:
2xf(x)+f′(x)=0Rearrange to write the derivative in terms of
f(x):
f′(x)=−2xf(x)Separate the variables by dividing both sides by
f(x):
f(x)1dxdf=−2xThis can be written as:
f1df=−2xdxIntegrate both sides:
∫f1df=∫−2xdxln∣f∣=−x2+CExponentiate both sides to solve for
f(x):
f(x)=Ce−x2Since
C is an arbitrary constant,
f(x)=e−x2 is the simplest matching form among the given options.
Answer:Option C:
e−x2