KCET 2026 Chemistry Solved Paper

Concept:For ethers, choose the longer carbon chain as the parent alkane.Name the smaller alkyl group attached to oxygen as an alkoxy substituent.Explanation:The given compound is $( \mathrm{CH}_3)_3\mathrm{C}-\mathrm{O}-\mathrm{C}_2\mathrm{H}_5$.The ethyl side, $-\mathrm{C}_2\mathrm{H}_5$, becomes the ethoxy group, $-\mathrm{O}-\mathrm{C}_2\mathrm{H}_5$.The tert-butyl side contains a longest chain of three carbons, so the parent hydrocarbon is propane.Number the propane chain to give substituents the lowest locants.Both the methyl group and the ethoxy group are attached to the middle carbon, which is carbon 2.At carbon 2, the substituents are $-\mathrm{CH}_3$ and $-\mathrm{OCH}_2\mathrm{CH}_3$.Write substituents alphabetically: ethoxy $(e)$ comes before methyl $(m)$.Therefore, the correct IUPAC name is 2-ethoxy-2-methylpropane.Answer:Option C. 2-ethoxy-2-methylpropane