The false statement is Option A. Reasoning: By definition, on an equipotential surface the potential V is the same everywhere, so any two points have ∆V=0 The work done in moving a charge q through a potential difference ∆V is W=q∆V=q×0=0 Hence it's incorrect to say the work is "not zero." The other options are all true: B: Equipotentials are surfaces of constant V. C: In a uniform field, equipotentials are equally spaced parallel planes. D: E is always perpendicular to equipotential surfaces.