To find the derivative of sinx with respect to logx, we need to use the concept of implicit differentiation and the chain rule. Let f(x)=sinx. We want to find
d(sinx)
d(logx)
. Using the chain rule, we have:
d(sinx)
d(logx)
=
d(sinx)
dx
⋅
dx
d(logx)
First, we calculate each part separately:
d(sinx)
dx
=cosx To find
dx
d(logx)
, consider that
d(logx)
dx
=
1
x
, hence:
dx
d(logx)
=x Putting it all together, we get:
d(sinx)
d(logx)
=cosx⋅x=xcosx Therefore, the derivative of sinx with respect to logx is xcosx.