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KCET 2025 Math Paper
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© examsnet.com
Question : 29
Total: 60
If a matrix
A
=
[
1
1
1
1
]
satisfies
A
6
=
k
A
′
, then the value of
k
is
32
1
1
32
6
Validate
Solution:
‌
A
=
[
1
1
1
1
]
‌
A
2
=
[
1
1
1
1
]
[
1
1
1
1
]
=
[
2
2
2
2
]
‌
A
3
=
[
2
2
2
2
]
[
1
1
1
1
]
=
[
4
4
4
4
]
=
[
2
2
2
2
2
2
2
2
]
‌
A
4
=
[
8
8
8
8
]
=
[
2
3
2
3
2
3
2
3
]
‌
A
6
=
[
2
5
2
5
2
5
2
5
]
=
2
5
[
1
1
1
1
]
⇒
2
5
=
32
‌
∴
k
=
32
© examsnet.com
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