Solution:
Isotonic solutions are those which have same osmotic pressure (Π = ππΆπ
π). But here we have different concentration of the solutions and also they have different vanβt Hoff factors (i). So the solutions for which the product of i and c will be same, will be isotonic.
a. For, 0.001 M β, π = 3. So π Γ πΆ = 3 Γ 0.001 = 0.003
For, 0.001 M π΄π2(ππ4)3 ,π = 5. So π Γ πΆ = 5 Γ 0.001 = 0.005
b. For, 0.01 M π΅ππΆπ2 , π = 3. So π Γ πΆ = 3 Γ 0.01 = 0.03
For, 0.001 M πΆππΆπ2 , π = 3. So π Γ πΆ = 3 Γ 0.001 = 0.003
c. For, 0.01 M β, π = 3. So π Γ πΆ = 3 Γ 0.01 = 0.03
For, 0.015 M πππΆπ, π = 2. So π Γ πΆ = 2 Γ 0.015 = 0.03
Thus 0.01 M π΅ππΆπ2 and 0.015 M πππΆπ are isotonic in nature.
d. For, 0.001 M π΄π2(ππ4)3, π = 5. So π Γ πΆ = 5 Γ 0.001 = 0.005
For, 0.01 M ππΆπ2,π = 3. So π Γ πΆ = 3 Γ 0.01 = 0.03
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