y2 = x → (1) x2 + y2 = 2x → (2) Equation (2) is a circle with centre (1, 0) and radius 1. Solving (1) and (2), we get the points of intersection (0, 0) and (1, 1) (x–1)2+y2 = 1 y2 = x (x–1)2 + x = 1 x2– x = 0 x(x – 1) = 0 x = 0, x = 1 area =