A = (3, 1, 6); B = (1, 3, 4) Mid-point of AB = (2, 2, 5) lies on the plane and d.r's of AB = (2, −2, 2) d.r's Of normal to plane = (1, −1, 1). AB is not perpendicular bisector ∴ A is not image of B. Statement-2 is correct but it is not correct explanation.