The percentage error in R can be minimized by adjusting the balance point near themiddle of the bridge, i.e., when 1, is close to 50 cm. This requires a suitable choice of S. Since
R
S
=
l1
100−l1
; Since here R : S = 0.9 : 97.1 then the value of S is nearly 33 times to that of R. In order to make this ratio 1 : 1, it is necessary to reduce the value of S nearly 1/33 times, i.e., nearly 3Ω .
