JEE Mains Model Paper 3

Here, magnification
m =

f

m+f

=

20

−30+20

= -2 =

hi

h0

⇒ hi = -2h0

So the image is real and inverted. Thus, due to upper lens image will be formed hi = -2 (-2cm) = 4 cm above upper principal axis and similarly for lower lens 4 cm belowlower principal axis. So the separation between the images is (4 + 4 + 4) cm = 12 cm
v = 12 × 1013 Hz