The part PUQ of the wire can be replaced by straight wire PQ and QWR replaced by QR. Force experienced by PQ is F = i (2B0) (√2r)
Force experienced by QR is F2 = i (3B0) (√2r) ∴ Resultant magnetic force acting on the wire is F = √F12+F22 F = i B0 r √2((2)2+(3)2) = √26 iB0 r