‌C=900µF ‌Q=CV=900×10−6×100=9×10−2=90‌MC Now
Common potential will be developed across both capacitors by kVL Total charge on left plates of capacitors should be conserved. ∴‌‌90‌mc+0=2cv0 ‌cv0=45‌mc
Heat dissipated =Ui−Uf [Change in energy stored in the capacitors] ‌=‌
1
2
‌
(90‌mc)2
900µF
−2×‌
1
2
‌
(45‌mc)2
900µF
[U=‌
Q2
2c
] ‌=‌
1
2×900×10−6
(8100−4050)×10−6 ‌=2.25‌Joule OR ‌‌ Heat ‌=‌